Write The Following Equation Of The Circle In General Form That Will Satisfy The Given Conditions, 3. The Center Is At (0,-9), And The Circle Passes T

Write the following equation of the circle in general form that will satisfy the given conditions

3. the center is at (0,-9), and the circle passes through (8,0).

 

Answer:

x² + y² + 18y - 64 = 0

Step-by-step explanation:

write the following equation of the circle in general form that will satisfy the given conditions  

3. the center is at (0,-9), and the circle passes through (8,0).

first, find the radius

use distance formula (center to a point that the circle passes)

d = √(x2 - x1)² + (y2 -y1)²

d = √(8 - 0)² + (0 - -9)²

d = √145

r = √145

Standard form: (x-h)² + (y-k)² = r²

where  h and k are the coordinates of the center of the circle

(x - 0)² + (y - -9)² = (√145)²

x² + (y + 9)² = 145

x² + y² + 18y + 81 - 145 = 0

x² + y² + 18y - 64 = 0


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